Day 15

Kirchoff's Law

  

The above picture is our circuit board used to determine the different currents on each resistor from electrical motor force, EMF.  The current at each resistor was measured with an multimeter.

 

After measuring the current at each resistor, the theoretical current was calculated by using Kirchoff's Law to determine the current at each resistor.  The calculations are shown below.  After obtaining the the theoretical values for current they were compared to the experimental values obtained through percent error.  Our percent error for most current were under 6 %.

 

The following picture is a circuit with resistors in parallel and in series. In order to prove that the R_equivalent equation follows the same value if done in an experiment.  A multimeter was used to measure the resistance of the collected resistors.

 

The Picture above and bellow displays a drawn circuit of the resistor with our theoretical value and experimental.

Day 14

Electric Potential Lab

 

In this laboratory experiment, the electric potential  on a special conductive paper.  A voltage source of 15 volts was the transmitted through the conductive paper on the indicated area.  The Voltage then was measured a distance a way from the indicated area for the voltage at a different distance.

 

The measured values obtain were then put into a spreadsheet on excel in which the electric potential was calculated using the equation (delta V)/(delta x)

The following are pictures are the questions answered from the lab hand out.

In the above picture the first question deals with the work done at a point were there is no electric field. the second question deals with the work done at distances were there exist a stronger electric field.

 

The above picture displays the work it takes to move further into the electric field.

 

In this picture we display that the (delta V)/(delta X) is has the same units as the electric field.

Day 13

In Class Quiz

In this quiz, we were assign to establish a dim lighting system.

 

After redoing the experiment, we found a method in which lighting in the light bulb was at the most dim.  This was done by setting the battery parallel to one another and creating a circuit between thus having a higher resistance as voltage traveled toward the light bulbs. 

 

 

This is a diagram of the light bulb quiz after being redone.

4.5 V compared to 9 V

The above graph displays in blue the 9 V and red 4.5 V emitted into water with the change in temperature.

The above picture displays our calculations for the 4.5 V.

This is a picture of our 9 V Calculations

This picture displays our percent uncertainty of change in temperature.  It was deduced that the current value obtained from the other group, 8.9 A, was wrong since it did not match our experimental values.

Day 12

Volts Vs. Current

In this experiment voltage was passed through an Amp reader and then through a resistor.  This was done for various different power outputs in order to obtain the different readings in current and voltage.

 

The picture above is a comparison between our resistor and the resistor from the group beside us.

The above picture is our data in comparison with the other groups 2 data.

The data above displays that voltage is proportional to current. Our data is in blue while the other group's is in red.  The fit line displays our graph as a voltage versus current graph using the equation V=IR.  Moreover, our slope in this case is our resistance in our resistor in which case we concluded that the other groups resistor was strong than ours.  Even though we both had very similar resistor, our difference in resistivity may be due to the systematic error in different equipment.

Resistance Lab

The above photos display the equipment used to calculate the resistance in different resistor of which each had a different length and/ or material, copper or nickel.

 

The above picture is our data collected from the experiment and the graph was plotted as Length versus Resistance. From this graph it was determined that in resistors of same material and diameter have a proportional relationship between length and resistance.  However, when the diameter of the wire increases and the length is consistent then the resistivity decreases as the area of the wire increase.  Therefore, displaying an inverse relationship.  As shown in the picture below.

 

Day 11

Active Physics Gauss's Law

This Activity was done to see how electric field is difference between a spherical shell and a sphere.

Day 10

Electric Flux

 

In this experiment we wanted to see the change in Flux as the plate changes in angle with respect to the electric field.  The nails in this case represents the electric field as it goes through the wire plate.  The necessary measurements need for this lab was the height and and hypotenuse lenght in order to get the, theta, angle between the normal vector of the plate with respect with the electric field.

The Graph above represents the Electric flux vs the change in angle.  The result was a Cosine wave.  This graph shows how flux is related to the equation of the dot product between E*dAcos(theta).

Active physics

The above picture displaces how the electric field is uniform within an enclosed sphere

The above photograph shows how the flux of to charges inside a closed sphere is depended upon the net charge inside.  Flux= (Q_enlcosed)/E_0

Day 9

Air Hockey

 

The Above displays how two protons were used to move the positive particle to the goal.

 

The above picture displays how to positive electron react with one another with respect to their electric field.

 

This picture represents a charge particle's electric field and potential field.

The above photo shows how an uncharged particle reacts in an electric field.

The above photo displays how a charge particle reacts in an electric field

The above pictures displays how force reacts with the electric field.  F= qE